The number of manganeses ions in tetrahedral and octahedral sites respectively in `Mn_3O_4` are

Options

A. one `Mn^(2+) and " two"Mn^(3+)` ions
B. one `Mn^(3+) and " two"Mn^(2+)` ions
C. two `Mn^(3+) and " two"Mn^(2+)` ions
D. two `Mn^(2+) and " two"Mn^(3+)` ions

Answer

To determine the number of manganese ions in tetrahedral and octahedral sites in `Mn3O4`, we can follow these steps:

### Step 1: Understand the Structure of `Mn3O4`
`Mn3O4` is a type of spinel structure. Spinels can be classified into two types: normal spinel and inverse spinel. In a normal spinel, the cations occupy specific sites based on their oxidation states.

### Step 2: Identify the Oxidation States
In `Mn3O4`, manganese can exist in two oxidation states:
- Mn²⁺ (oxidation state +2)
- Mn³⁺ (oxidation state +3)

### Step 3: Determine the Distribution of Manganese Ions
In a normal spinel structure:
- The A cation (Mn²⁺) occupies the tetrahedral sites.
- The B cation (Mn³⁺) occupies the octahedral sites.

In `Mn3O4`, we have:
- 1 Mn²⁺ ion (A)
- 2 Mn³⁺ ions (B)

### Step 4: Count the Ions in Each Site
Based on the spinel structure:
- Tetrahedral sites will have 1 Mn²⁺ ion.
- Octahedral sites will have 2 Mn³⁺ ions.

Thus, the number of manganese ions in tetrahedral and octahedral sites respectively in `Mn3O4` is:
- Tetrahedral sites: 1 Mn²⁺
- Octahedral sites: 2 Mn³⁺

### Final Answer
The number of manganese ions in tetrahedral and octahedral sites in `Mn3O4` are 1 and 2, respectively.

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