In the given reaction `C_6H_5-CH_2-Br+AgCNrarrX` (major product) [X] will be

Options

A. `C_6H_5-CH_2CN`
B. `C_6H_5-CH_2NC`
C. `C_6H_5CH_2CONH_2`
D. `C_6H_5CONH_2`

Answer

To determine the major product of the reaction between `C6H5-CH2-Br` and `AgCN`, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- `C6H5-CH2-Br` (Benzyl bromide)
- `AgCN` (Silver cyanide)

### Step 2: Understand the Nature of the Reactants
- `AgCN` is a covalent compound, which means that the bond between silver and carbon is stronger compared to ionic compounds. This affects how the nucleophile will behave in the reaction.

### Step 3: Identify the Nucleophile
In this reaction, the cyanide ion (`CN-`) acts as a nucleophile. It has a lone pair of electrons on the nitrogen atom, making it an ambident nucleophile, meaning it can attack from either the carbon or nitrogen.

### Step 4: Mechanism of the Reaction
1. The nucleophile (`CN-`) will attack the carbon atom of the benzyl bromide (`C6H5-CH2-Br`).
2. This attack will lead to the displacement of the bromine atom (Br) as a leaving group.
3. The stronger bond in `AgCN` means that the attack will occur through the carbon of the `CN-` rather than the nitrogen.

### Step 5: Formation of the Product
Upon the nucleophilic attack, the product formed will be:
- `C6H5-CH2-NC` (Benzyl isocyanide)

### Conclusion
The major product `[X]` of the reaction `C6H5-CH2-Br + AgCN` is **Benzyl isocyanide** (`C6H5-CH2-NC`).

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