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Calculate the resonance enegry of N(2)O ...

Calculate the resonance enegry of `N_(2)O` form the following data
`Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1)`
Bond enegry of `N-=N, N=N, O=O,` and `N=O` bond is `946, 418, 498`, and `607 kJ mol^(-1)`, respectively.

A

`+8.85 " KJ mol"^(-1)`

B

`-88 " KJ mol"^(-1)`

C

`-8.8 " KJ mol"^(-1)`

D

`+88 " KJ mol"^(-1)`

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The correct Answer is:
B
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Calculate the resonance energy of N_(2)O from the following data : DeltaH_(f)^(@) of N_(2)O = 82 kJ mol^(-1) , Bond energies of N equivN , N = N , O =O and N =O bonds are 946, 418, 498 and 607 kJ mol^(-1) respectively.

Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mol"^(-1)

Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mole"^(-1)

Calculate the resonance enegry of NO_(2) ( :O-N=O: ) The measured enthalpy formation of NO_(2)(Delta_(f)H^(Theta)) is 34 kJ mol^(-1) . The bond energies given are: N -O rArr 222 kJ mol^(-1) N -= N rArr 946 kJ mol^(-1) O = O rArr 498 kJ mol^(-1) N = O rArr 607 kJ mol^(-1)

H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(g) DeltaH =- 242 kJ mol^(-1) Bond energy of H_(2) and O_(2) is 436 and 500 kJ mol^(-1) , respectively. What is bond energy of O-H bond?

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