In the reaction `CH_3COOH+HCOOH overset(Mn"O"//300^@C)rarr[X]` [X] will be

Options

A. `HCHO`
B. `CH_3CHO`
C. `CH_3COCH_3`
D. `CH_3-COOH`

Answer

To solve the question, we need to analyze the reaction between acetic acid (CH₃COOH) and formic acid (HCOOH) in the presence of manganese oxide (MnO) at a temperature of 300°C.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are acetic acid (CH₃COOH) and formic acid (HCOOH).
- Acetic acid has a two-carbon structure, while formic acid has a one-carbon structure.

2. **Understand the Reaction Conditions**:
- The reaction occurs in the presence of manganese oxide (MnO) at a high temperature of 300°C.
- MnO acts as an oxidizing agent in this reaction.

3. **Determine the Oxidation and Reduction Processes**:
- In this reaction, formic acid (HCOOH) undergoes oxidation, which means it will lose hydrogen and be converted to carbon dioxide (CO₂).
- Acetic acid (CH₃COOH) undergoes reduction, which means it will gain hydrogen or lose oxygen, resulting in the formation of acetaldehyde (CH₃CHO).

4. **Write the Products**:
- The oxidation of formic acid (HCOOH) results in carbon dioxide (CO₂).
- The reduction of acetic acid (CH₃COOH) results in acetaldehyde (CH₃CHO).

5. **Final Products**:
- Therefore, the products of the reaction are:
- Carbon dioxide (CO₂) from the oxidation of formic acid.
- Acetaldehyde (CH₃CHO) from the reduction of acetic acid.

6. **Identify the Product [X]**:
- The question asks for the product [X] formed in this reaction.
- Since acetaldehyde (CH₃CHO) is one of the products formed, we conclude that [X] is acetaldehyde.

### Conclusion:
The product [X] formed in the reaction is **CH₃CHO (acetaldehyde)**.

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