Product of the given reaction `CH_3CH_2-CH=CH_3overset(SiO_2)rarr` will be

Options

A. `CH_3-overset(OH)overset(|)(CH)-CH=CH_2`
B. `overset(OH)overset(|" ")(CH_2)-CH_2-CH=CH_2`
C. `CH_3-CH_2-underset(O)underset(||)C-CH_3`
D. `CH_3-CH_2-underset(O)underset(||)C-CHO`

Answer

To solve the reaction of 1-butene (CH₃CH₂-CH=CH₂) with SiO₂, we will follow these steps:

### Step 1: Identify the Reactant
The reactant is 1-butene, which has the structure:
\[ \text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2 \]

### Step 2: Understand the Role of SiO₂
Silica (SiO₂) acts as a catalyst in this reaction and is known for facilitating selective hydroxylation, specifically allylic hydroxylation. This means that it will introduce a hydroxyl (-OH) group at the allylic position relative to the double bond.

### Step 3: Determine the Allylic Position
In 1-butene, the double bond is between the second and third carbon atoms. The allylic positions are the carbon atoms adjacent to the double bond. Therefore, the allylic positions are:
- The carbon atom at position 2 (CH₂)
- The carbon atom at position 3 (CH)

### Step 4: Perform the Hydroxylation
In allylic hydroxylation, the hydrogen atom from the allylic carbon (position 2) is replaced with a hydroxyl group (-OH). The reaction can be represented as follows:
- The hydrogen atom from the second carbon (CH₂) is removed, and an -OH group is added.

The product will then be:
\[ \text{CH}_3\text{CHOH}\text{CH}=\text{CH}_2 \]

### Step 5: Write the Final Product
Thus, the final product of the reaction is:
\[ \text{CH}_3\text{CHOH}\text{CH}=\text{CH}_2 \]

### Conclusion
The product of the reaction of 1-butene with SiO₂ is:
\[ \text{CH}_3\text{CHOH}\text{CH}=\text{CH}_2 \]