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An endotthermic reaction is non-spontane...

An endotthermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then:

A

`DeltaH " is " -ve , DeltaS ` is +ve

B

`DeltaH and DeltaS` both are + ve

C

`DeltaH and DeltaS` both are - ve

D

`DeltaH " is " +ve , DeltaS ` is -ve

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The correct Answer is:
B
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Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then

If an endothermic reaction is non - spontaneous at freezing of water and becomes feasible at its boiling point, then

A reaction is non-spontaneous when:

Boiling point of water

The following reaction is non-spontaneous

NTA MOCK TESTS-NTA NEET SET 92-CHEMISTRY
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