`C_6H_5-overset(OH)overset(|)(CH)-CH_3` can be prepared form which of the following combinations

Options

A. `C_6H_5-CHO and CH_3MgCl`
B. `C_6H_5MgBr and CH_3CHO`
C. `{:(" "O),(" "||" "and NaBH_4),(C_6H_5-C-CH_3):}`
D. All of these

Answer

To solve the question regarding the preparation of the compound C6H5-CHOH-CH3, we will analyze each of the provided combinations step by step.

### Step-by-Step Solution:

1. **Identify the Target Compound**:
The target compound is C6H5-CHOH-CH3, which can be recognized as a secondary alcohol derived from a phenyl group (C6H5) and a hydroxymethyl group (CHOH) attached to a methyl group (CH3).

2. **Examine the First Option**:
The first option is C6H5-CHO (benzaldehyde) reacting with CH3MgCl (a Grignard reagent).
- The reaction involves the nucleophilic attack of the Grignard reagent on the carbonyl carbon of benzaldehyde.
- This results in the formation of a tertiary alcohol after hydrolysis.
- The product formed is C6H5-CHOH-CH3, which matches our target compound.

3. **Examine the Second Option**:
The second option is C6H5MgBr (a Grignard reagent) reacting with acetaldehyde (CH3CHO).
- The Grignard reagent attacks the carbonyl carbon of acetaldehyde.
- This forms a compound that can be hydrolyzed to yield C6H5-CHOH-CH3.
- Thus, this combination also leads to the desired product.

4. **Examine the Third Option**:
The third option involves the reduction of a ketone (C6H5-CO-CH3) using sodium borohydride (NaBH4).
- Sodium borohydride acts as a reducing agent, converting the ketone into an alcohol.
- The product formed after the reduction is again C6H5-CHOH-CH3, which is our target compound.

5. **Examine the Fourth Option**:
The fourth option states that all of the above combinations can yield the target compound.
- Since we have confirmed that each of the first three options can produce C6H5-CHOH-CH3, this option is correct.

### Conclusion:
All three combinations can prepare the compound C6H5-CHOH-CH3. Therefore, the correct answer is **all of these**.