In the given reaction `CH_3-CH_2-Broverset(Na//"dryether")rarr` Product, product will be

Options

A. Pure n - butane
B. Mixture of butane and hydrogen
C. Mixture of butane, ethene and ethane
D. Mixture of ethene and ethane

Answer

To solve the given question regarding the reaction of `CH3-CH2-Br` with sodium in dry ether, we will follow these steps:

### Step 1: Identify the Reactants
The reactant is `CH3-CH2-Br`, which is bromoethane. Sodium (Na) is used in the presence of dry ether.

**Hint:** Recognize that sodium is a reducing agent and dry ether is a solvent that supports radical reactions.

### Step 2: Understand the Reaction Mechanism
The reaction proceeds through a free radical mechanism. Sodium donates an electron to the bromine atom, generating a bromine radical and an ethyl radical.

**Hint:** Remember that in free radical reactions, the breaking of a bond leads to the formation of radicals.

### Step 3: Formation of Radicals
The ethyl radical (`CH3-CH2•`) can combine with another ethyl radical or react with other radicals formed during the reaction.

**Hint:** Consider the possibility of radical recombination, which can lead to the formation of larger alkane chains or different products.

### Step 4: Possible Products
1. **Butane Formation**: The ethyl radical can combine with another ethyl radical to form butane (`CH3-CH2-CH2-CH3`).
2. **Ethylene Formation**: If two ethyl radicals combine in a different manner, they could also form ethylene (`CH2=CH2`).

**Hint:** Think about the types of products that can arise from radical coupling and rearrangement.

### Step 5: Conclusion
The primary product of the reaction will be butane, but ethylene can also be formed depending on the reaction conditions and the pathways taken by the radicals.

**Final Answer:** The product will be butane (`C4H10`), with the possibility of ethylene (`C2H4`) as a minor product.