Consider the following reaction `CH_3-CH=CH_2overset(Br_2//NaCl)rarr` Product of the reaction will be

Options

A. Only 1,2 - dibromopropane
B. Only 1- bromo -2- chloropropane
C. Only -2- bromo -1- chloropropane
D. Mixture of 1,2 dibromopropane and 1 - bromo -2- chloropropane

Answer

To solve the problem, we need to analyze the reaction of propene (CH₃-CH=CH₂) with bromine (Br₂) in the presence of sodium chloride (NaCl). Here’s a step-by-step breakdown of the reaction:

### Step 1: Identify the Reactants
The reactants in this reaction are propene (CH₃-CH=CH₂) and bromine (Br₂) in the presence of sodium chloride (NaCl).

**Hint:** Look at the structure of propene and note the presence of the double bond, which is reactive.

### Step 2: Mechanism of the Reaction
When Br₂ is added to the alkene (propene), the double bond (π bond) attacks one of the bromine atoms. This leads to the formation of a bromonium ion intermediate.

**Hint:** Remember that the π bond acts as a nucleophile and attacks the electrophilic Br₂.

### Step 3: Formation of the Bromonium Ion
The attack of the π bond on Br₂ results in the formation of a cyclic bromonium ion. This intermediate has a positive charge on one carbon and a bromine atom attached to the other carbon.

**Hint:** Visualize the bromonium ion as a three-membered ring where one carbon is bonded to a bromine atom.

### Step 4: Nucleophilic Attack by Chloride Ion
In the presence of NaCl, the chloride ion (Cl⁻) can act as a nucleophile. It attacks the more substituted carbon of the bromonium ion from the opposite side (anti-addition).

**Hint:** The chloride ion will attack the carbon that is more stable due to sterics, which is typically the more substituted carbon.

### Step 5: Final Product Formation
After the nucleophilic attack by Cl⁻, we get two products:
1. 1-bromo-2-chloropropane (CH₃-CH(Cl)-CH₂Br)
2. 1,2-dibromopropane (CH₃-CH(Br)-CH₂Br)

**Hint:** Consider that anti-addition leads to the formation of two different products due to the different positions of the halogens.

### Step 6: Conclusion
The final products of the reaction are a mixture of 1-bromo-2-chloropropane and 1,2-dibromopropane.

**Final Answer:** The correct option is that the product of the reaction will be a mixture of 1,2-Dibromo and 1-Bromo-2-Chloropropane.