In the reaction sequence `CH_3-CH_2-COOHoverset(H_2O_2)rarr[X]overset(Delta)rarr[Y]` [Y] will be

Options

A. `CH_3-overset(OH)overset(|)(CH)-COOH`
B. `CH_2=CH-COOH`
C. `overset(OH" ")overset(|" ")(CH_2)-CH_2-COOH`
D. Lactide

Answer

To solve the problem, we will break down the reaction sequence step by step.

### Step 1: Identify the starting compound
The starting compound is propanoic acid, which has the molecular formula \( \text{CH}_3\text{CH}_2\text{COOH} \).

### Step 2: Reaction with Hydrogen Peroxide (\( \text{H}_2\text{O}_2 \))
When propanoic acid reacts with hydrogen peroxide (\( \text{H}_2\text{O}_2 \)), it forms peroxypropanoic acid. This is a type of peracid formed through the addition of a peroxy group to the carboxylic acid. The reaction can be represented as follows:

\[ \text{CH}_3\text{CH}_2\text{COOH} + \text{H}_2\text{O}_2 \rightarrow \text{CH}_3\text{CH}_2\text{C(O)O-OH} \quad (\text{Peroxypropanoic acid}) \]

### Step 3: Heating the product
The next step involves heating the peroxypropanoic acid. Upon heating, a dehydration reaction occurs where a water molecule is eliminated. The reaction can be summarized as:

\[ \text{CH}_3\text{CH}_2\text{C(O)O-OH} \xrightarrow{\Delta} \text{CH}_3\text{CH}_2\text{C=O} + \text{H}_2\text{O} \]

### Step 4: Identify the final product
The final product \( Y \) after heating is propanoyl (or propanoyl chloride if the reaction conditions are specific), which has the structure:

\[ \text{CH}_3\text{CH}_2\text{C=O} \]

### Conclusion
Thus, the final product \( Y \) is propanoyl.

### Final Answer
**Y will be propanoyl (or propanoyl chloride depending on specific conditions).**

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