`BeO+CrarrCO+Xoverset(H_2O)rarrBe(OH)_2+Y`; X and Y in the above sequence are respectively

Options

A. `Be_2C and C_2H_2`
B. `Be_2C and CO_2`
C. `Be_2C and CH_4`
D. `Be_2C and C_2H_6`

Answer

To solve the reaction sequence given in the question, we need to identify the compounds X and Y in the reaction:

**Given Reaction:**
\[ \text{BeO} + \text{Cr} \rightarrow \text{CO} + X \overset{(H_2O)}{\rightarrow} \text{Be(OH)}_2 + Y \]

### Step-by-Step Solution:

1. **Identify the Reaction of Beryllium Oxide with Carbon:**
- When beryllium oxide (BeO) reacts with carbon (C), it produces carbon monoxide (CO) and a beryllium carbide (Be2C).
- Thus, we can write:
\[ \text{BeO} + \text{C} \rightarrow \text{CO} + \text{Be}_2\text{C} \]
- Here, X is identified as **Be2C**.

2. **Reacting Beryllium Carbide with Water:**
- The next part of the reaction involves beryllium carbide (Be2C) reacting with water (H2O).
- The reaction of beryllium carbide with water produces beryllium hydroxide (Be(OH)2) and methane (CH4).
- Thus, we can write:
\[ \text{Be}_2\text{C} + 4\text{H}_2\text{O} \rightarrow 2\text{Be(OH)}_2 + \text{CH}_4 \]
- Here, Y is identified as **CH4**.

3. **Final Identification of X and Y:**
- From the above reactions, we conclude:
- X = Be2C
- Y = CH4

### Final Answer:
X and Y in the above sequence are respectively:
- **X = Be2C**
- **Y = CH4**