The volume strength of 3.57 M solution hydrogen peroxide (at STP) is Report your answer by rounding it upto nearest whole number

Options

A. 20
B. 40
C. 25
D. 36

Answer

To find the volume strength of a 3.57 M solution of hydrogen peroxide (H2O2) at STP, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Volume Strength**: Volume strength of a solution is defined as the volume of oxygen gas (in liters) that can be produced by 1 liter of the solution when it decomposes completely. For hydrogen peroxide, the decomposition reaction is:
\[ 2 H_2O_2 \rightarrow 2 H_2O + O_2 \]

2. **Calculate Moles of H2O2**: The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. Therefore, in a 3.57 M solution, there are 3.57 moles of H2O2 in 1 liter of solution.

3. **Determine Moles of O2 Produced**: From the decomposition reaction, we see that 2 moles of H2O2 produce 1 mole of O2. Therefore, the moles of O2 produced from 3.57 moles of H2O2 can be calculated as follows:
\[ \text{Moles of } O_2 = \frac{3.57 \text{ moles of } H_2O_2}{2} = 1.785 \text{ moles of } O_2 \]

4. **Convert Moles of O2 to Volume at STP**: At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Thus, the volume of O2 produced can be calculated by multiplying the moles of O2 by the molar volume:
\[ \text{Volume of } O_2 = 1.785 \text{ moles} \times 22.4 \text{ L/mole} = 39.984 \text{ L} \]

5. **Final Calculation of Volume Strength**: Since the volume strength is defined as the volume of O2 produced per liter of solution, we find that the volume strength of the 3.57 M H2O2 solution is approximately 39.984.

6. **Rounding to the Nearest Whole Number**: Finally, we round 39.984 to the nearest whole number:
\[ \text{Volume Strength} \approx 40 \]

### Final Answer:
The volume strength of the 3.57 M solution of hydrogen peroxide at STP is **40**.