How many `-OH` groups are present in one molecules of sucrose?

Answer

To determine how many -OH groups are present in one molecule of sucrose, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure of Sucrose**:
- Sucrose is a disaccharide composed of two monosaccharides: glucose and fructose.

2. **Identify the Components**:
- Glucose has 5 -OH groups in its structure.
- Fructose also has 5 -OH groups in its structure.

3. **Count the -OH Groups**:
- Since sucrose is formed by the combination of glucose and fructose, we need to count the -OH groups from both components.
- Total -OH groups from glucose = 5
- Total -OH groups from fructose = 5

4. **Combine the Counts**:
- Total -OH groups in sucrose = 5 (from glucose) + 5 (from fructose) = 10

5. **Adjust for the Formation of Sucrose**:
- When glucose and fructose combine to form sucrose, one -OH group from glucose and one -OH group from fructose are involved in the glycosidic bond formation, which means they are no longer free -OH groups.
- Therefore, we subtract 2 from the total count of -OH groups.
- Total -OH groups in sucrose = 10 - 2 = 8

### Final Answer:
- There are **8 -OH groups** in one molecule of sucrose.