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Let the function f(x)=|x+1|. The number ...

Let the function `f(x)=|x+1|`. The number of values of `x in [-2,2]` for which `f(x-3),f(x-1)` and `f(x+1)` are in the arithmetic progression is

A

0

B

1

C

2

D

inifinte

Text Solution

Verified by Experts

The correct Answer is:
C
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