The mean and variance of 10 observations...

The mean and variance of 10 observations are found to be 10 and 5 respectively. On rechecking it is found that an observation 5 is incorrect. If the incorrect observation is replaced by 15, then the correct variance is

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The mean and variance of 20 observations are found to be 10 and 4 respectively. On rechecking, it was found that an observation 8 is incorrect. If the wrong observation is omitted, then the correct variance is

The mean and variance of 20 observations are found to be 10 and 4. respectively. On rechecking, it was found that an observation 9 was incorrect and the correct observation was 11. Then the correct variance is

The mean and variance of 10 observation are found to be 10 and 4 respectively. On rechecking it was found that an observation 8 was incorrect. If it is replaced by 18, then the correct variance is

The mean and standard deviation of 20 observations are found to be 10 and 2 respectively. On rechecking, it was found that an observation 8 was incorrect. Find the new standard deviation if wrong item is omitted.

The mean and standard deviation of 20 observations are found to be 10 and 2 respectively.One rechecking,it was found that an observation 8 was incorrect.Calculate the correct mean and standard deviation in each of the following cases.(i) If wrong item is omitted (ii) If it is replaced by 12.

The mean and standard deviation of 18 observations are found to be 7 and 4 respectively. On rechecking it was found that an observation 12 was misread as 21. Calculate the correct mean and standard deviation.

The mean and standard deviation of "15" observations were found to be "12" and "3" respectively.On rechecking it was found that an observation was read as "10" in place of "12" .If mu and sigma^(2) denote the mean and variance of the correct observations respectively,then 15(mu+mu^(2)+sigma^(2)) is equal to

The mean and variance of five observations are 6 and 4 respectively.If three of these are 5,7 and 9, find the other two observations.

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