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A particle of mass 2 kg moves in the xy ...

A particle of mass `2 kg` moves in the `xy` plane under the action of a constant force `vec(F)` where `vec(F)=hat(i)-hat(j)`. Initially the velocity of the particle is `2hat(j)`. The velocity of the particle at time `t` is

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The force acting on the body is `vec(F)=(5hat(i)-2hat(j))N` while the displacement, `vec(x)=6hat(i)m`
The work done `= vec(F).vec(x)(5hat(i)-2hat(j)).6hat(i)=30J`
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