A particle is projected with a speed v at an angle `theta` with the horizontal. Find the mean power delivered by gravity during the ascent of the particle.

Explanation

To find the mean power delivered by gravity during the ascent of a particle projected with a speed \( v \) at an angle \( \theta \) with the horizontal, we can follow these steps:

### Step 1: Identify the components of velocity
The initial velocity \( v \) can be broken down into its horizontal and vertical components:
- \( u_x = v \cos \theta \) (horizontal component)
- \( u_y = v \sin \theta \) (vertical component)

### Step 2: Determine the time of ascent
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