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Excess pressure inside one soap bubble i...

Excess pressure inside one soap bubble is four times that of other. Then the ratio of volume of first bubble to second one is

A

` 1:64`

B

`1:4`

C

`64:1`

D

`1:2`

Text Solution

Verified by Experts

`(P_(1))/(P_(2)) = 4 ` or `P_(1) = 4P_(2)`
` (4T)/(r_(1)) = (4 xx 4T)/(r_(2)) rArr (r_(1))/(r_(2)) = 1/4`
` (V_(1))/(V_(2)) = (r_(1)^(3))/(r_(2)^(3)) = (1/4)^(3) = 1/64`
Hence ( A ) is correct
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