Effective acceleration due to gravity is given by
`g.=g-Romega^(2)cos^(2)theta`.
Hence, change in acceleration due to gravity is given as.
`Deltag=g.-g=-Romega^(@)cos^(2)theta`
At equator `theta=0`.
Hence, `g.=g=-Romega^(2)`
`=-6.4xx10^(6)xx(7.27xx10^(-5))^(2)=-0.0338m//s^(2)`
`g.-g=-3.38cm//s^(2)`.
The negative sign signifies that, the decrease in gravitational acceleration is due to the rotation of earth.
