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In the figure shown two particles m & M ...

In the figure shown two particles m & M are interconnected by an inextensible and light string. M is in equilibrium due to revolution of particle m in horizontal plane as shown in the figure. Now M is pulled down slowly through a distance l/2. Find the change in angular speed of particle m.

Text Solution

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The correct Answer is:
`Delta omega = 3 sqrt((Mg)/(ml))`
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