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A steel wire of length 4 m and diameter ...

A steel wire of length 4 m and diameter 5 mm is stretched by 5kg-wt. Find the increase in its length if the Young's modulus of steel wire is `2.4 xx 10^(12) dyn e cm^(-2)`

Text Solution

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Here , l=4m =400 cm ,
2r=5 mm or r=2.5 mm =0.25 cm
f=5 kg -wt=5000 g -wt = 5000 x 980 dyne
`Deltal`=? , `Y=2.4xx10^12 "dyne/cm"^2`
As `Y=F/(pir^2)xxl/(Deltal) rArr Deltal=(Fl)/(pir^2Y)`
`=((5000xx980)xx400)/((22//7)xx(0.25)^2xx2.4xx10^12)`= 0.0041 cm
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