Two air columns of resonance appatus, 100cm and 101 cm long give 17 beats in 20 second, when each is sounding its fundamental mode. Calculate the velocity of sound.
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17 beats are produced in 20 seconds. Therefore beat frequency =17/20 `l_1`=1.0 and `l_2`=1.01 m , Now, `n_1=V/(4l_1), n_2=V/(4l_2)` Given that one end is closed `rArr (n_1-n_2)=V/4 (1/l_1-1/l_2)` `=V/4 ((l_2-l_1)/(l_1l_2))` or `V=(4(n_1-n_2)(l_1-l_2))/((l_1-l_2))` `=4xx17/20xx(1)(1.01)xx1/0.01` = 343.4 m/s
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