Home
Class 12
PHYSICS
A stationary wave is given by y = 5 si...

A stationary wave is given by
`y = 5 sin (pi x)/( 3) cos 40 pi t`
where `x and y` are in `cm and t` is in second.
a. What are the amplitude and velocity of the component wave whose superposition can give rise to this vibration ?
b. What is the distance between the nodes ?
c. What is the velocity of a particle of the string at the position ` x = 1.5 cm when t = 9//8 s`?

Text Solution

Verified by Experts

The correct Answer is:
(a)5/2 cm, 120 cm/s (b)3 cm , (c) Zero
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY AND WAVES

    FIITJEE|Exercise Assignment Problems (Objective) Level-I|40 Videos
  • ELASTICITY AND WAVES

    FIITJEE|Exercise Assignment Problems (Objective) Level-II|15 Videos
  • ELASTICITY AND WAVES

    FIITJEE|Exercise Assignment Problems (Subjective) Level-I (Fill in the blanks )|5 Videos
  • CURRENT ELECTRICITY

    FIITJEE|Exercise Comprehension -4|3 Videos
  • ELECTROMAGNETIC INDUCTION

    FIITJEE|Exercise EXERCISE|9 Videos

Similar Questions

Explore conceptually related problems

A standing wave is given by y=5"sin" (pi x)/(20) cos 40 pit , where x and y are in cm and t is in second. What is the minimum distance between a node and the adjacent antinode ?

A string vibrate according to the equation y = 5 sin ((pi x)/(3)) cos (40 pi t) where x and y in cm's and t is in second. (i) What is the equation of incident and reflected wave ? (ii) What is the distance between the adjacent nodes ? (iii) What is the velocity of the particle of the string at the position x = 1.5 cm when t = (9)/(8) sec ?

The equation of a stationary wave is given by y=6sin(pi)//(x)cos40pit Where y and x are given in cm and time t in second. Then the amplitude of progressive wave is

The equation of a stationary wave is represented by y=2sin((2pix)/(3))sin(3pit) Where y and x are in metre and t is in second. Calculate amplitude, frequency, wavelength and velocity of the component waves whose superposition has produced these vibrations.

The equation of stationary wave along a stretched string is given by y=5 sin (pix)/(3) cos 40 pi t , where x and y are in cm and t in second. The separation between two adjacent nodes is

The following equation represents standing wave set up in a medium , y = 4 cos (pi x)/(3) sin 40 pi t where x and y are in cm and t in second. Find out the amplitude and the velocity of the two component waves and calculate the distance adjacent nodes . What is the velocity of a medium particle at x = 3 cm at time 1//8 s ?