Light of wavelength `600 nm` is incident normally on a slit of width `3 mm`. Calculate linear width of central maximum on a screen kept `3 m` away from the slit.

Explanation

Here, `lambda = 600 nm = 6 xx 10^(-7)m`
`a=3mm= 3xx10^(3)m`
D=3m
`therefore` width of central maximum = `(2Dlambda)/(a)`
=`( 2xx3xx6xx10^(-7))/(3xx10^(-3))=12xx10^(-4)m=1.2mn`