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An electromagnetic wave of frequency v=3...

An electromagnetic wave of frequency `v=3.0 MHz` passes from vacuum into a dielectric medium with permittivity `epsilon=4.0`. Then

A

wavelength is doubled and the frequency remains unchanged

B

wavelength is doubled and frequency becomes half

C

wavelength is halved and frequency remains unchanged

D

wavelength and frequency both remain unchanged

Text Solution

Verified by Experts

The correct Answer is:
C

Refractive index,`mu=sqrt((epsilon)/(epsilon_(0)))=2`
Speed and wavelength of wave will becomes half the frequency remaining unchanged (frequency of a wave depends on the source as due to refraction, it is assumed that the energy is conserved, hv remains the same)
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