In a plane electromagnetic wave, magnetic field oscillates with amplitude` 1.6 xx 10^(-11)T` Find the maximum value of electric field.

Answer

To find the maximum value of the electric field (E₀) in a plane electromagnetic wave given the amplitude of the magnetic field (B₀), we can use the relationship between the electric field and the magnetic field in electromagnetic waves. The formula we will use is:

\[ E_0 = B_0 \times c \]

where:
- \( E_0 \) is the maximum electric field,
- \( B_0 \) is the maximum magnetic field (given as \( 1.6 \times 10^{-11} \, T \)),
- \( c \) is the speed of light in vacuum (approximately \( 3 \times 10^8 \, m/s \)).

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Amplitude of the magnetic field, \( B_0 = 1.6 \times 10^{-11} \, T \)
- Speed of light, \( c = 3 \times 10^8 \, m/s \)

2. **Use the Formula for Maximum Electric Field:**
- Substitute the values into the formula:
\[ E_0 = B_0 \times c \]

3. **Calculate the Electric Field:**
- Substitute \( B_0 \) and \( c \):
\[ E_0 = (1.6 \times 10^{-11} \, T) \times (3 \times 10^8 \, m/s) \]

4. **Perform the Multiplication:**
- Calculate:
\[ E_0 = 1.6 \times 3 \times 10^{-11} \times 10^8 \]
\[ E_0 = 4.8 \times 10^{-3} \, V/m \]

5. **Final Result:**
- The maximum value of the electric field is:
\[ E_0 = 4.8 \times 10^{-3} \, V/m \]

### Conclusion:
The maximum value of the electric field in the plane electromagnetic wave is \( 4.8 \times 10^{-3} \, V/m \).