If the origin and the roots of the equation`z^2 + az + b=0` forms an equilateral triangle then show that the area of the triangle is `(sqrt3)/(4) b.`

The origin and the roots of the equation z^(2)+pz+q=0 form an equilateral triangle If - -

The length of a median of an equilateral triangle is 12sqrt(3) cms. Then the area of the triangle is :

Two vertices of an equilateral triangle are origin and (4, 0). What is the area of the triangle ?

If lambda in R such that the origin and the non-real roots of the equation 2z^(2)+2z+lambda=0 form the vertices of an equilateral triangle in the argand plane, then (1)/(lambda) is equal to

If z_1 and z_2 are the roots of the equation z^2+az+12=0 and z_1 , z_2 forms an equilateral triangle with origin. Find absa