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If omega is complex cube root of that 1/...

If `omega` is complex cube root of that `1/(a+omega)+1/(b+omega)+1/(c+omega)=2omega^2` and `1/(a+omega^2)+1/(b+omega^2)+1/(c+omega^2)=2omega` then the value of `1/(a+1)+1/(b+1)+1/(c+1)=`

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