Two numbers a and b are selected from the set of natural number then the probability that `a^2 + b^2` is divisible by 5 is

Two numbers a and b are chosen at random from the set of first 30 natural numbers. The probability that a^(2)-b^(2) is divisible by 3 is:

Two numbers are randomly selected from the first 100 natural numbers. The probability the product is divisible by 17 is

Two number a and b aer chosen at random from the set of first 30 natural numbers.Find the probability that a^(2)-b^(2) is divisible by 3 .

Three distinct numbers are selected from the first 100 natural numbers. The probability that all the three numbers are dicisible by 2 and 3 is

let integer p and q are selected randomly from first 60 natural numbers then find the probability that 7^(p)+7^(q) is divisible by 5.

Two numbers a and b are chosen at random from the set {1,2,3,..,5n}. The probability that a^(4)-b^(4) is divisible by 5, is

Two distinct numbers are selected at random from the first twelve natural numbers. The probability that the sum will be divisible by 3 is :

Two number are randomly selected from the set of first 9natural numbers.If 'p' be the probability that their sum is odd given one of the selected digit is 2 and 'q' be the probability that 2 is one of the selected digit given their sum is odd then.