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India plays, 2,3 and 5 matches against P...

India plays, 2,3 and 5 matches against Pakistan, Srilanka and West Indies respectively. Probability that India win a match against Pakistan, Srilanka and West Indies is 0.6,0.5 and 0.4 respecitvely. If india win a match , what is the probability that it was against Pakistan.

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To solve the problem, we will use Bayes' theorem to find the probability that India played against Pakistan given that they won a match. ### Step-by-step Solution: 1. **Identify the Matches Played:** - India plays 2 matches against Pakistan. - India plays 3 matches against Sri Lanka. - India plays 5 matches against West Indies. - Total matches = 2 + 3 + 5 = 10 matches. 2. **Calculate the Probability of Playing Against Each Team:** - Probability of playing against Pakistan, \( P(P) = \frac{2}{10} = 0.2 \) - Probability of playing against Sri Lanka, \( P(SL) = \frac{3}{10} = 0.3 \) - Probability of playing against West Indies, \( P(WI) = \frac{5}{10} = 0.5 \) 3. **Calculate the Probability of Winning Against Each Team:** - Probability of winning against Pakistan, \( P(W|P) = 0.6 \) - Probability of winning against Sri Lanka, \( P(W|SL) = 0.5 \) - Probability of winning against West Indies, \( P(W|WI) = 0.4 \) 4. **Calculate the Total Probability of Winning, \( P(W) \):** Using the law of total probability: \[ P(W) = P(W|P) \cdot P(P) + P(W|SL) \cdot P(SL) + P(W|WI) \cdot P(WI) \] Substituting the values: \[ P(W) = (0.6 \cdot 0.2) + (0.5 \cdot 0.3) + (0.4 \cdot 0.5) \] \[ P(W) = 0.12 + 0.15 + 0.20 = 0.47 \] 5. **Apply Bayes' Theorem:** We want to find \( P(P|W) \), the probability that India played against Pakistan given that they won: \[ P(P|W) = \frac{P(W|P) \cdot P(P)}{P(W)} \] Substituting the values: \[ P(P|W) = \frac{0.6 \cdot 0.2}{0.47} \] \[ P(P|W) = \frac{0.12}{0.47} \] 6. **Calculate the Final Probability:** \[ P(P|W) \approx 0.2553 \] ### Final Answer: The probability that India played against Pakistan given that they won a match is approximately \( 0.2553 \) or \( \frac{12}{47} \).
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