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A bag contains 3 white balls and 2 black...

A bag contains 3 white balls and 2 black balls, another contains 5 white and 3 black balls, if a bag is chosen at random and a ball is drawn from it. What is the probability that it is white ?

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To find the probability of drawing a white ball from one of the two bags, we can follow these steps: ### Step 1: Identify the contents of each bag - **Bag A**: Contains 3 white balls and 2 black balls. - **Bag B**: Contains 5 white balls and 3 black balls. ### Step 2: Calculate the total number of balls in each bag - **Total in Bag A**: 3 (white) + 2 (black) = 5 balls - **Total in Bag B**: 5 (white) + 3 (black) = 8 balls ### Step 3: Determine the probability of choosing each bag Since a bag is chosen at random, the probability of choosing either bag is: - \( P(A) = \frac{1}{2} \) - \( P(B) = \frac{1}{2} \) ### Step 4: Calculate the probability of drawing a white ball from each bag - **Probability of drawing a white ball from Bag A**: \[ P(W|A) = \frac{\text{Number of white balls in A}}{\text{Total balls in A}} = \frac{3}{5} \] - **Probability of drawing a white ball from Bag B**: \[ P(W|B) = \frac{\text{Number of white balls in B}}{\text{Total balls in B}} = \frac{5}{8} \] ### Step 5: Use the law of total probability to find the overall probability of drawing a white ball The overall probability of drawing a white ball can be calculated as follows: \[ P(W) = P(A) \cdot P(W|A) + P(B) \cdot P(W|B) \] Substituting the values we calculated: \[ P(W) = \left(\frac{1}{2} \cdot \frac{3}{5}\right) + \left(\frac{1}{2} \cdot \frac{5}{8}\right) \] ### Step 6: Simplify the expression Calculating each term: - For Bag A: \[ \frac{1}{2} \cdot \frac{3}{5} = \frac{3}{10} \] - For Bag B: \[ \frac{1}{2} \cdot \frac{5}{8} = \frac{5}{16} \] Now, we need a common denominator to add these fractions. The least common multiple of 10 and 16 is 80. - Convert \(\frac{3}{10}\) to a fraction with a denominator of 80: \[ \frac{3}{10} = \frac{3 \times 8}{10 \times 8} = \frac{24}{80} \] - Convert \(\frac{5}{16}\) to a fraction with a denominator of 80: \[ \frac{5}{16} = \frac{5 \times 5}{16 \times 5} = \frac{25}{80} \] Now we can add: \[ P(W) = \frac{24}{80} + \frac{25}{80} = \frac{49}{80} \] ### Final Answer The probability that the ball drawn is white is: \[ \boxed{\frac{49}{80}} \]
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