Suppoe a simple consist of the integers 1,2,….2n, the probability of choosing an integer k is proportion to log k . Show that the conditional probability of choosing the integer 2, given that even integer is chosen is `(log2)/((n) log 2 +log(n!))` .

A sample pace runninum integers 1,2,3,....100. The probability of choosing an integer his proportional to ln k .The conditional probability of choosing the integer '2, given that even integer is choosen,the integer is

If the probability of choosing an integer 'k' out of 2n integers 1, 2, 3, …, 2n is inversely proportional to k^4(1lekle2n) . If alpha is the probability that chosen number is odd and beta is the probability that chosen number is even, then (A) alpha gt 1/2 (B) alpha gt 2/3 (C) beta lt 1/2 (D) beta lt 2/3

If n is a positive integer then int_(0)^(1)(ln x)^(n)dx is :

If a,b,c are any three consecutive integers, prove that log(1+ac)=2log b

If a,b,c are any three consecutive integers, prove that log(1+ac)=2log b

The number of values of n such that log_(n) 2^(231) is an integer is (n in N)

The least integer greater than (log)_(2)(15)*(log)_((1)/(6))2*(log)_(3)(1)/(6) is ...