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From 4m+1 tickets numbered as 1,2 ,….4m+...

From `4m+1` tickets numbered as 1,2 ,….4m+1…. Three tickets are chosen at random. Find out the probability that the numbers are in A.P. with even common difference.

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The correct Answer is:
`(6m)/((16m^(2)-1))`
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FIITJEE-PROBABILITY-ASSIGNMENT PROBLEMS (SUBJECTIVE) Level -II
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