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Three numbers are selected at random one by one with replacement from the numbers 1,2,3,….60. The probability that the A.M. of the numbers selected is 15 is.

A

`(.^(48)C_(2))/(.^(60)C_(3))`

B

`(.^(47)C_(2))/(.^(60)C_(3))`

C

`(.^(44)C_(2))/((60)^3)`

D

`(.^(45)C_(2))/((60)^3)`

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