A and B take turns in throwing two dice, the first to throw 9 being awarded the prize. Show that their chance of winning are in the ratio 9:8.

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both dice will be awarded the prize. If A throws first, then the probability that B wins the game is 9//17 b. 8//17 c. 8//9 d. 1//9

Two person A and B take turns in throwing a pair of dice.The first person to through 9from both dice will win the game.If A throwns fisrt then the probability that B wins the game is.

A and B throw a pair of die turn by turn.The first to throw 9 is awarded a prize.If A starts the game,show that the probability of A getting the prize is (9)/(7)

Two persons A and B throw two dice each. If A throws a sum of 9 then the probability of Y throwing a sum greater than that of A is

Getting a 9 on throwing a dice is ______ event .

In a single throw of two dice, the probability of getting a total of 7 or 9 is

A,B and C in order throw an unbiased coin. The first who throws head wins.Find the respective probabilities of winning

In a single throw of two dice, find the probability of obtaining 'a total of 8'.