20mL of 0.2M `Al_(2)(SO_(4))_(3)` is mixed with 20mL of 0.6M `Bacl_(2)`.Concentration of `Al^(3+)`ion in the solution will be:

Options

A. `0.2 M`
B. `10.3 ` M
C. `0.1 M`
D. `0.25` M

Answer

A

Explanation

`{:(" "Al_(2)(SO_(4))_(3) " "+ BaCl_(2) " "to BaSO_(4) downarrow + AlCl_(3)),("Initial Meq. "20 xx 0.2 xx 6 " "20 xx 0.6 xx 2 " 0 0"),(" "=24" "=24),("Final Meq. "0" 0 24 24"):}`
`[Al^(3+)] = 24/(40 xx 3) = 0.2 M`