25 ml of `H_(2)O_(2)` solution was added to the excess of acidified Kl solution . The iodine so liberated required 40 ml of `0.1` N sodium thiosulphate solution. Calculate the normality of `H_(2)O_(2)` solution :

Options

A. `0.08`
B. `0.16`
C. `0.02`
D. `0.20`

Answer

B

Explanation

Let the normality of `H_(2)O_(2)` soln be`N_(x)`.
No. of milliequivalents of `Na_(2)S_(2)O_(3) ` = No. of milliequivalents of `H_(2)O_(2)`
`40 xx 0.1 = 25 xx N_(x)`
` N_(x) = (40 xx 0.1)/25 = 0.16` N