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Copper has fcc crystal structure. Assumi...

Copper has fcc crystal structure. Assuming an atomic radius of 130 pm for copper atom (Cu = 63.54) :
(a) What is the length of unit cell of Cu ?
(b) what is the volume of the unit cell ?
(c ) How many atoms belong to the unit cell ?
(d) Find the density of Cu.

Text Solution

Verified by Experts

As we know
`rho = (n xx M_(m))/(N_(o)xx a^(3))`,
(a) For FCC structure
`4r = sqrt(2)a`
`a = 2sqrt(2)r`
`= 2sqrt(2)xx130 p m= 367.64 p m`
(b) Volume of unit cell `= a^(3)=(n xxM_(m))/(N_(o)xx rho)=(3.67xx10^(-8))^(3)=4.94xx10^(-23)cm^(3)`
(c ) n = 4
(d) `rho = (4xx63.54)/(6.023xx10^(23)xx(3.67xx10^(-8))^(3))=8.54 gm//cm^(3)`
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Knowledge Check

  • Copper has the fcc crystal structure . Assuming an atomic radius of 130 pm for copper atom (Cu = 63.54 ) . Find the density of Cu .

    A
    `4.94` g/cc
    B
    `3.67` g/cc
    C
    4 g/cc
    D
    `8.54` g/cc
  • Copper has the fcc crystal structure . Assuming an atomic radius of 130 pm for copper atom (Cu = 63.54 ) , what is the length of unit cell of Cu ? Find the density of Cu ?

    A
    `267.64 p m , 8.54 g cm ^(-3)`
    B
    `267.64 p m , 5.48 g cm^(-3)`
    C
    `367.64 p m , 9.24 g cm ^(-3)`
    D
    `367.64 p m , 8.54 g cm ^(-3) `
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    A
    0.56 nm
    B
    0.24 nm
    C
    0.96 nm
    D
    0.4 nm
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