Calculate percentage hydrolysis in `0.003` M aqueous solution `K_(a)` for HOCN = `3.35 xx 10^(-4) `and `K_(w) = 10^(-14)`

Explanation

To calculate the percentage hydrolysis of HOCN in a 0.003 M aqueous solution, we will follow these steps:

### Step 1: Write the hydrolysis reaction
The hydrolysis of HOCN (hydrocyanic acid) can be represented as:
\[ \text{HOCN} + \text{H}_2\text{O} \rightleftharpoons \text{OCN}^- + \text{H}_3\text{O}^+ \]

### Step 2: Identify the given values
- Concentration of HOCN, \( C = 0.003 \, \text{M} \)
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