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Equal volume of 0.02 M KCl and 0.02 M ...

Equal volume of 0.02 M KCl and 0.02 M `K[Ag(CN)_(2)]` are mixed , then the precipitate of AgCl will Ksp `AgCl = 1.5 xx 10^(-10)`
`K (K[Ag (CN)_(2)]) = 4xx 10^(-22)`

A

Not form

B

Form

C

May or May not form , depending upon the volume of solution

D

None of these

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