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The freezing point of an aqueous solutio...

The freezing point of an aqueous solution of KNC containing `0.1892 "mol" kg^(-1)` was `0.74^(@)C`. On adding `0.95` mol of Hg `(CN)_(2)` the freezing point of solution was `-0.53^(@)C`. Assuming that complex is formed to the equation `Hg(CN)_(2)+mCN^(-) to [Hg(CN)_(m+2)]^(n-)`
Find. m

Text Solution

Verified by Experts

The correct Answer is:
`m=2`
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