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Addition of 0.643g of a compound to 50mL...

Addition of `0.643g` of a compound to `50mL` of benzene (density: `0.879g mL^(-1))`lower the freezing point from `5.51^(@)C` to `5.03^(@)C`. If `K_(f)` for benzene is `5.12 K kg mol^(-1)`, calculate the molar mass of the compound.

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The correct Answer is:
`M_(2)=156.0` g/mol
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