The equivalent conductances of sodium chloride, hydrochloric acid and sodium acetate at infinite dilution are 126.45, 426.16 and `91.0 ohm^(-1) cm^(2) eq^(-1)`, respectively at `25^(@)C`. Calculate the equivalent conductance of acetic acid at infinite dilution.

Explanation

According to Kohlrausch.s law,
`wedge_(ooCH_(3)COONa) =lambda_(CH_(3)COO^(-))+lambda_(Na^(+))=910 ...........(i)`
`wedge_(oo HCl)=lambda_(H^(+))+lambda_(H^(+))+lambda_(Cl^(-))=426.16 ...........(ii)`
`wedge_(oo NaCl)=lambda_(Na^(+))+lambda_(Cl^(-))=126.45 ......(iii)`
Adding eqs. (i) and (ii) and substractinge eq. (iii),
`lambda_(CH_(3)COO^(-))+lambda_(Na^(+))+lambda_(H^(+))+lambda_(Cl^(-))- lambda_(Na^(+))-lambda_(Cl^(-))`
=91.0+426.16-126.45
`lambda_(CH_(3)COO^(-))+lambda_(H^+)=wedge_(oo CH_(3)COOH)=390.7" ohm"^(-1) cm^(2)" equiv"^(-1)`