Home
Class 12
CHEMISTRY
A direct current deposits deposits 54 g ...

A direct current deposits deposits 54 g of silver (Atomic mass = 108) during electrolysis. How much aluminimum (Atomic mass =27) would be deposited from aluminium chloride solution by the same amount of electricity ?

A

4.5g

B

5.4g

C

54g

D

2.7g

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    FIITJEE|Exercise Assignment Problems (Objective) Level-1 Reasoning Type Questions|6 Videos
  • ELECTROCHEMISTRY

    FIITJEE|Exercise Assignment Problems (Objective) Level -II|20 Videos
  • ELECTROCHEMISTRY

    FIITJEE|Exercise Assignment Problems (Subjective) Level -II|15 Videos
  • CONCEPT OF ACIDS AND BASES

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|4 Videos
  • ELECTROPHILIC AROMATIC SUBSTITUTION

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS INDICATED BY DIGITAL INTERGER|1 Videos

Similar Questions

Explore conceptually related problems

If 54 g of silver is deposited during an electrolysis reaction, how much aluminium will be deposited by the same amount of electric current?

the number of electrons required to deposit 1g equivalent aluminium (At. Wt. =27) from a solution of aluminium chloride will be

An electric current is passed through silver nitrate solution using silver electrodes. 15.28 g of silver was found to be deposited on catode. What will be the weight of copper deposited on cathode if same amount of electricity is passed through copper sulphate solution using copper electrodes?

An electric current is passed through silver nitrated solution using silver electrodes . 10. 79 g of silver qas found to be deposited on the cathode fi the same amount of electricity is passed through copper sulphate solutin using copper electrodes. the weihgt of copper deposited on teh cathode is .

The "mole"s of electrons required to deposit 1 gm equivalent aluminium (at wt. =27) from a solution of aluminium chloride will be:

How many atoms of calcium will be deposited from a solution of CaCl_(2) by a current of 5mA flowig for 60s?

FIITJEE-ELECTROCHEMISTRY-Assignment Problems (Objective) Level-1
  1. Cost of electricity for the production of X litre H(2) at STP at catho...

    Text Solution

    |

  2. What current is to be passed for 0.25 sec for deposition of certain we...

    Text Solution

    |

  3. A direct current deposits deposits 54 g of silver (Atomic mass = 108) ...

    Text Solution

    |

  4. The specific conductance of saturated solution of AgCl is found to be ...

    Text Solution

    |

  5. The specific conductivity of N/10 KCl solution at 20^(@)C is 0.0212 oh...

    Text Solution

    |

  6. Resistance of a conductvity cell filled with a solution of an electrol...

    Text Solution

    |

  7. The molar conductivities of KCl, NaCl and KNO(3) are 152,128 and 111" ...

    Text Solution

    |

  8. E^(@) for the electrochemical cell Zn(s)|Zn^(2+) 1 M (Aq.)||Cu^(2+) ...

    Text Solution

    |

  9. Calculate the emf of the following concentration cell at 25^(@)C: Ag...

    Text Solution

    |

  10. Two electrolytic cells, one containing acidified ferrous sulphate and ...

    Text Solution

    |

  11. E^(c-) of Mg^(2+)|Mg,Zn^(2+)|Zn, and Fe^(2+)|Fe are -2.37V,-0.76V, and...

    Text Solution

    |

  12. If the half-cell reaction A+e^(-)toA^(-) has a large negative reductio...

    Text Solution

    |

  13. When a rod of metal A Is dipped in an aqueous solution of metal ion, B...

    Text Solution

    |

  14. The absolute value of which of the following cannot be determined?

    Text Solution

    |

  15. Stronger the oxidizing agent, greater is the

    Text Solution

    |

  16. What is incorrect among the following statements regarding a galvanic ...

    Text Solution

    |

  17. In a Galvanic cell involving the redox reaction: A^(2+)+ B((s)) Left...

    Text Solution

    |

  18. How much will the reduction potential of a hydrogen electrode change w...

    Text Solution

    |

  19. Passage of one ampere current through 0.1M NI(NO3)2 solution using Ni ...

    Text Solution

    |

  20. The charge required for the oxidation of one mole Mn3O4 into MnO4^2- i...

    Text Solution

    |