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Chose the correct acidity orders among t...

Chose the correct acidity orders among the following.
(1) `H_(3)AsO_(4) < H_(3)PO_(4)`
(2) `H_(2)CO_(3) >H_(3)BO_(3)`
(3) `H_(3)AsO_(4)< H_(3)AsO_(2)`

A

1 and3

B

1 and 2

C

3 only

D

2 and 3

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct acidity orders among the given compounds, we will analyze each statement one by one. ### Step 1: Analyze Statement (1) `H₃AsO₄ < H₃PO₄` 1. **Structure and Resonance**: - Draw the structures of both acids. - For `H₃AsO₄`, the conjugate base after losing an H⁺ would be `H₂AsO₄⁻`, which has resonance stabilization. - For `H₃PO₄`, the conjugate base after losing an H⁺ would be `H₂PO₄⁻`, which also has resonance stabilization. 2. **Electronegativity**: - Phosphorus (P) is more electronegative than Arsenic (As). This means that the negative charge in the conjugate base of `H₃PO₄` is more stabilized compared to that in `H₃AsO₄`. 3. **Conclusion**: - Since the conjugate base of `H₃PO₄` is more stable due to higher electronegativity, `H₃PO₄` is more acidic than `H₃AsO₄`. - Therefore, the order `H₃AsO₄ < H₃PO₄` is correct. ### Step 2: Analyze Statement (2) `H₂CO₃ > H₃BO₃` 1. **Structure and Resonance**: - Draw the structures of both acids. - For `H₂CO₃` (carbonic acid), the conjugate base after losing an H⁺ would be `HCO₃⁻`, which has resonance stabilization. - For `H₃BO₃` (boric acid), the conjugate base after losing an H⁺ would be `H₂BO₃⁻`, which does not have significant resonance stabilization. 2. **Conclusion**: - The conjugate base of `H₂CO₃` is more stable due to resonance, while `H₃BO₃` lacks such stabilization. - Therefore, `H₂CO₃` is more acidic than `H₃BO₃`, making the order `H₂CO₃ > H₃BO₃` correct. ### Step 3: Analyze Statement (3) `H₃AsO₄ < H₃AsO₂` 1. **Structure and Resonance**: - Draw the structures of both acids. - For `H₃AsO₄`, the conjugate base after losing an H⁺ would be `H₂AsO₄⁻`, which has resonance stabilization. - For `H₃AsO₂`, the conjugate base after losing an H⁺ would be `H₂AsO₂⁻`, which also has resonance stabilization but has fewer oxygen atoms to stabilize the negative charge. 2. **Conclusion**: - `H₃AsO₄` is more acidic than `H₃AsO₂` because it has more oxygen atoms that can stabilize the negative charge in the conjugate base. - Therefore, the order `H₃AsO₄ < H₃AsO₂` is incorrect. ### Final Conclusion - The correct acidity orders are: - (1) `H₃AsO₄ < H₃PO₄` is **correct**. - (2) `H₂CO₃ > H₃BO₃` is **correct**. - (3) `H₃AsO₄ < H₃AsO₂` is **incorrect**. Thus, the correct options are (1) and (2) only.
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