If a die is thrown twice, then the number of possible outcomes is ...............

Answer

To determine the number of possible outcomes when a die is thrown twice, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Problem**: We need to find the total number of outcomes when a single die is thrown two times. Each die has 6 faces numbered from 1 to 6.

2. **Identify Outcomes for One Throw**: When a die is thrown once, the possible outcomes are {1, 2, 3, 4, 5, 6}. This means there are 6 possible outcomes for a single throw.

3. **Calculate Outcomes for Two Throws**: Since the die is thrown twice, we need to consider the outcomes for both throws. The outcome of the first throw does not affect the outcome of the second throw.

4. **Use the Counting Principle**: According to the counting principle, if one event can occur in 'm' ways and a second independent event can occur in 'n' ways, then the total number of outcomes for both events is m × n.

5. **Apply the Counting Principle**: Here, for the first throw, there are 6 outcomes and for the second throw, there are also 6 outcomes. Therefore, the total number of outcomes when throwing the die twice is:
\[ \text{Total Outcomes} = 6 \times 6 = 36 \]

6. **Conclusion**: The total number of possible outcomes when a die is thrown twice is 36.

### Final Answer:
The number of possible outcomes is **36**.

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