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Two different dice are tossed together. Find the probability (i) of getting a doublet (ii)of getting a sum of 10, of the numbers on two dice

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The correct Answer is:
Doublets are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)
Required probability `=(6)/(36)=(1)/(6)`
(ii) Sum 10 cases (4, 6), (5, 5), (6, 4)
Required probability `=(3)/(36)=(1)/(12)`
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