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If A( 1,2) , B( 4,3) and C ( 0,0) are th...

If A( 1,2) , B( 4,3) and C ( 0,0) are three vertices of parallelogram ABCD , find the coordinates of D.

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To find the coordinates of point D in the parallelogram ABCD, where A(1, 2), B(4, 3), and C(0, 0) are given, we can use the property that the diagonals of a parallelogram bisect each other. ### Step-by-Step Solution: 1. **Identify the coordinates of points A, B, and C:** - A = (1, 2) - B = (4, 3) - C = (0, 0) 2. **Use the midpoint formula to find the midpoint of AC:** The midpoint M of a line segment with endpoints (x1, y1) and (x2, y2) is given by: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] For points A(1, 2) and C(0, 0): \[ M_{AC} = \left( \frac{1 + 0}{2}, \frac{2 + 0}{2} \right) = \left( \frac{1}{2}, 1 \right) \] 3. **Let the coordinates of point D be (x, y). Find the midpoint of BD:** Using the same midpoint formula for points B(4, 3) and D(x, y): \[ M_{BD} = \left( \frac{4 + x}{2}, \frac{3 + y}{2} \right) \] 4. **Set the midpoints equal to each other:** Since the midpoints of diagonals AC and BD are equal, we can set them equal: \[ \left( \frac{4 + x}{2}, \frac{3 + y}{2} \right) = \left( \frac{1}{2}, 1 \right) \] 5. **Equate the x-coordinates:** \[ \frac{4 + x}{2} = \frac{1}{2} \] Multiply both sides by 2: \[ 4 + x = 1 \] Solving for x: \[ x = 1 - 4 = -3 \] 6. **Equate the y-coordinates:** \[ \frac{3 + y}{2} = 1 \] Multiply both sides by 2: \[ 3 + y = 2 \] Solving for y: \[ y = 2 - 3 = -1 \] 7. **Conclusion:** The coordinates of point D are: \[ D = (-3, -1) \] ### Final Answer: The coordinates of point D are (-3, -1).
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