The angular momentum of electrons in d orbital is equal to

Options

A. `sqrt(6)h`
B. `sqrt(2)h`
C. `2sqrt(3)h`
D. `0 h`

Explanation

To find the angular momentum of electrons in a d orbital, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Azimuthal Quantum Number (L)**:
- The azimuthal quantum number (L) corresponds to the type of orbital. For d orbitals, L = 2.

2. **Use the Formula for Angular Momentum**:
- The formula for the angular momentum (L) of an electron in an orbital is given by:
\[ L = \sqrt{L(L + 1)} \cdot \frac{h}{2\pi} \]
- Here, \( h \) is Planck's constant.

3. **Substitute the Value of L**:
- For d orbitals, substitute L = 2 into the formula:
\[ L = \sqrt{2(2 + 1)} \cdot \frac{h}{2\pi} \]

4. **Calculate the Expression Inside the Square Root**:
- Calculate \( 2 + 1 = 3 \), so:
\[ L = \sqrt{2 \cdot 3} \cdot \frac{h}{2\pi} \]
- This simplifies to:
\[ L = \sqrt{6} \cdot \frac{h}{2\pi} \]

5. **Final Expression for Angular Momentum**:
- Therefore, the angular momentum of electrons in a d orbital is:
\[ L = \sqrt{6} \cdot \frac{h}{2\pi} \]

### Conclusion:
The angular momentum of electrons in a d orbital is equal to \( \sqrt{6} \cdot \frac{h}{2\pi} \).