The value of Planck's constant is `6.63 xx 10^(-34)Js`. The speed of light is `3xx10^(17)nm s^(-1)`. Which value is the closed to the wavelength in nanometers of a quantum of light with frequency `6 xx 10^(10)s^(-1)`?

Options

A. 10
B. 25
C. 50
D. 75

Answer

C

Explanation

(c) Given , Planck's constant,
`h=6.63xx10^(-34) Js`
Speed of light, `c=3xx10^(17) nm s^(-1)`
Frequency of quantam light
`v=6xx10^(15) s^(-1)`
wavelength, `lambda=?`
We know that, `v=(c)/(lambda)`
or `lambda=(c)/(v)=(3xx10^(17))/(6xx10^(15))=0.5xx10^(2) nm`
`= 50 nm`